1.2-0.4x^2=0

Solution for 1.2-0.4x^2=0 equation:

1.2-0.4x^2=0

a = -0.4; b = 0; c = +1.2;
Δ = b2-4ac
Δ = 02-4·(-0.4)·1.2
Δ = 1.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.92}}{2*-0.4}=\frac{0-\sqrt{1.92}}{-0.8}
=-\frac{\sqrt{}}{-0.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.92}}{2*-0.4}=\frac{0+\sqrt{1.92}}{-0.8}
=\frac{\sqrt{}}{-0.8}
$